Models for multiplication

Hello students, In ICSE syllabus for class 3 maths we multiply various numbers which are also repeated in 4th grade math. To multiply the numbers we follow some models so that we can easily multiply. Models are the easy representation of anything. Now I am going to show you some models for multiplication.
Skip counting: - In this model like we have numbers 1 2 3 4 5 6 7 8 9 10 11 12 and so on and we want 2's table than we can skip one number and we can take next number and apply this process as many time, then we will get 2 4 6 8 10 12 and so on...
Repeated Addition: - In this we can add repeated numbers, by doing this we will also get the same result. For example in this row 7 8 4 6 3 7 4 3 4 7 6 3 4 6 3, 7 is appearing at three times. If we add the 7 + 7 + 7 than we get 21 and if we multiply the 7 from 3 times ( because 7 is appearing in that row at 3 times ) 7 * 3 = 21. So both will produce same result.
Sets : - In this model like we have 3 sets and every set contain the 7 elements than the multiplication result will be 3 * 7 = 21.
Combination : - In this model, we make a combination of similar elements and then multiply them.
Arrays : - In this we multiply the numbers row and column wise.
Scale model : - Generally used in image type objects. More understand by graphically.
Models simplifies the process of multiplication.

I hope the information about the multiplication models will make sense to Grade III students.

In upcoming posts we will discuss about Describing events and Percents problems in mathematics. Visit our website for information on worksheets on rational numbers

Division problems

Math's subject is a collection of various types of operations. These operations are used on the number systems. In the Grade III, Grade 4 and also in 5th grade math of Karnataka state board books we study the most popular operations like addition, subtraction, division and multiplication. 

Division problems is a mathematical operation that divides the number into two different portions. The operation of division can be represented by the ÷ symbol. The division operation ÷ generally known as obelus.

For example 4 divided by 2 is 2, because when four is divided into two portions , each part has two equal numbers. Any number divided by one is equal to the actual given number. We can divide the number by the zero then result will be zero. So, in the mathematics division by zero is not allowed. In the multiplication when two numbers are multiplied to each other then result will be equal or greater then the actual given number. But in the division process the result will be equal or less then the given numbers. In the simple meaning we can say that division is the inverse operation of the multiplication operation. For performing the division operation on the given numbers, it is necessary to be familiar with the table of different numbers. In the below example we show you the process of dividing the numbers with the help of described steps. Improve you division skills by reading this.

Example: Solve the given problems of division 325 / 10?

Solution: The above given situation is the division situation of two numbers. Here the number to be divided into is known as dividend of division that is 325 and the number which divides the dividend are known as divisor that is 10.

step 1:arrange the numbers: 10 ) 325 (

step 2: In the above 10 is a two digit number so we need to take two digit number of dividend for division. The result will be write on the right hand side of dividend.

10 ) 325 ( 32.5

     - 30

    _______

         25

       -20

    _______

         50          (note: here by putting decimal point into answer we can add one

         50                      zero with the reminder )

     ________

               0

In upcoming posts we will discuss about Models for multiplication and Addition and subtraction. Visit our website for information on probability worksheets

0 and 1 in multiplication/division

In  grade III of ICSE board, while learning about the whole numbers and its properties, we cannot omit the role of 0 and 1 in multiplication division, we are going to learn how 0 and 1 in multiplication and addition work.
0 and 1 in multiplication: When 0 and 1 are multiplied with  any natural number, then they produce the following output:
If 0 is multiplied with any number say n, then the result is always zero . i.e. 0 * n = 0.
 On another hand, If 1 is multiplied with any number say n, then the result is always the number itself i.e. n * n = n.
 Thus we get the following results: 23* 1 = 23  and  23 * 0 = 0
                                                                145 * 1 = 145 and 136 * 0 = 0

 Now let us see the effect of these numbers on division:
We say that if there exist a natural number n, then following division properties work:
If 0 is divided by  any number say n, then the result is always zero . i.e. 0 / n = 0 and if  any number is divided by zero, then we get the result as “ no answer “.
If any number n is divided by 1, the result is the number itself and if 1 is divided by any number , then the result we get is the multiplicative inverse of that number, so we say n / 1 = n and 1 / n is the multiplicative inverse of the number n
We have the following examples to illustrate it : ( 0 / 5 ) = 0, ( 0 / 57 ) = 0
This property of 1 makes the number 1 as the “multiplicative Identity” and the property of zero is said as “power of zero”.

In upcoming posts we will discuss about Division problems and Multiplication and division situations. Visit our website for information on Perimeter of a Rectangle Formula

Multiplication problems

Hi Friends! in this online math tutor free session we will discuss about multiplication problems. Problems of multiplication are defined as the process of adding same number n times means when a number is added multiple times then this large process is short by using the multiplication. There are some multiplication problems and properties of multiplication that are useful for grade III students that are as follows:
As if there are addition of six for five times then (6 + 6 + 6 + 6 + 6) is equal to (6 * 5) that is equal to 30 and we easily understand that is a short method then the addition.
If there are problem related with finding the number of things in the equal groups means if there are four group of students and each have 9 students then total students are find by the help of multiplication as total number of students = 4 * 9 = 36 students.
If there are problems related to the arrays that means if there are number of rows 5 and number of columns in each row are 5 then find the number of total columns in the table.
This is also one type of multiplication problem and it is solved as:
Total number of columns = no of rows * no of columns in single row
Total number of columns = 5 * 5 = 25.
There are also some problems that related with the comparison means if the one object's value is n times to the other then this is also solved by the multiplication as understand by an example if Ana have
9 $ and Jenny have 4 times more than Ana then how many rupees Jenny have ?
So the total money of Jenny = 4 * money Of Ana
= 4 * 9
= 36 $
So by the multiplication we can easily find such types of question in very short period of time.

In upcoming posts we will discuss about 0 and 1 in multiplication/division and Negative numbers. Visit our website for information on CBSE 10th science syllabus

Estimation in addition and subtraction

Hi Friends! In today's online math tutoring free session we will talk about Estimation in addition and subtraction. In the mathematical language, estimation refers to calculating the value that is near to the actual value. It means that estimation value is a guess value of the real calculated value. It is usually performed by thought or sometime calculation involved in it. Suppose Jennifer buys some product from market and she thought that she will have to pay near $100. The process of estimation can also be executed in the mathematics. In the mathematics estimation processes are usually performed with the operations like addition and subtraction fractions. This topic helps the students of Grade III to understand the concept of estimation in addition and estimation in subtraction.
Estimation in addition: It is quick way to estimate the total of two or more numbers by rounding each number. After that we add these rounded numbers. This obtained solution is not an exact answer but close enough to the actual value for some purpose. To perform the estimation we need to remember two things:
a) First perform the rounding operation with the given numbers
b) After that add the rounded numbers
In the given example we show you the process of estimation with addition:
Example: Add the given numbers 356 and 678?
Solution: In the first step we round off the numbers 356 into 400 and 678 into 700
Then in second step we add the rounded values of the numbers
400 + 700 = 1100
If we add the actual value the solution will be
356 + 678 = 1034
Estimation of subtraction: It is quick and easier way to estimate the difference value of two numbers by rounding the numbers. The solution would not be exact value but close enough to the actual value for some purpose.
In estimation of subtraction we need to focus on two things:
a) Round off the each given term that will be subtracted.
b) After that perform the subtraction of the rounded numbers.


In upcoming posts we will discuss about Multiplication problems and Positive numbers. Visit our website for information on biology syllabus for class 10 ICSE

Inverse relationship of multiplication and division

Inverse relationship of multiplication and division helps the student of grade III . It is important to know that multiplication and division are the inverse processes. This means when a number is multiplied with other then the answer of it divide by any one of the number in the expression gives the other number in the expression it is understand by an example and you can play Rational Numbers Multiplicative Inverse Worksheets also. In the Inverse relationship of multiplication it is shows as if an expression 4 * 5 = 20 then inverse relationship is
20 / 4 = 5 ;
20 / 5 = 4 .Theses expression shows the relationship that are inverse in the way that when multiply 4 with 5 then it gives 20 and 20 is divided by 4 or 5 then it gives the other number in the given expression as 5 or 4 respectively .
When we talk about the Inverse relationship of division it is also shown as above Inverse relationship of multiplication as if an rational expressions 21 / 3 = 7 then it shows the inverse relationship as by multiplying the result with the divisor of the given expression as
3 * 7 = 21 or
7 * 3 = 21 .These expression shows the inverse relationship of division as when 21 is divided by the 3 it gives the answer 7 and according to the inverse relationship when 7 is multiplied with 3 or 3 is multiplied with 7 it gives the 21 that is the dividend .
So by these examples we easily understand the inverse relationship of multiplication and division . So these properties of multiplication and division are helpful in calculation where in three number only two are known and other one is unknown then by this user can easily find the answer .In the next session we are going to discuss 0 and 1in multiplication 0r division.

In upcoming posts we will discuss about Estimation in addition and subtraction and Factors and products. Visit our website for information on syllabus of economics for ICSE class 12

Multiplication facts/tables

In online tutoring for free for Grade III, we will be learning about the Multiplication tables and Multiplication facts
 Let us first learn what multiplication is. Multiplication means repeated addition. Multiplication is represented by  a sign “ * “. Now we see that when we write 3 * 5, it means 5 is added 3 times and it can be expressed as 5 + 5 + 5 = 15
 Also we have 3 * 5 = 15. To make the process of multiplication easier, the multiplication tables are formed, which are learned orally by the tiny tots in smaller grades
We express the table of any number n as
N * 1 = n
N *  2  = 2 times n
N * 3 = 3 times n
N  * 4  = 4 times n
And it … proceeds till
N * 10 = 10 times n
Now following the above rule we write a table of 3 as:
3 * 1 = 3
3 * 2 = 6
 3 * 3 = 9
 3 * 4 = 12
3 * 5 = 15
 3 * 6 = 18
 3 * 7 = 21
3 * 8 = 24
 3 * 9 = 27
 3 * 10 = 30
Now we look at the multiplication fact: (get more detail here)
We must remember that if we write  3 * 4  or we write 4 * 3 it will produce the same result.
 Thus for any division fact , there exist 2 multiplication facts. Let us try it  with some example:
 If we are given a division fact 30 / 5 = 6 what are the two multiplication facts for it:
 The above division expression can be written as :
5 * 6 = 30 , which means that 6 added 5 times gives 30.
or we will write 6 * 5 = 30, which means  5 added 6 times gives 30.

In upcoming posts we will discuss about Inverse relationship of multiplication and division and Equivalent fractions. Visit our website for information on ICSE syllabus for class 3 maths

Unit cost

In Grade III, Today as online tutors we are going to  learn about Unit cost of any article. Let us first define unit cost: Unit Cost of any article is the cost of the object in one  unit, this unit varies from object to object. If we are going to buy vegetables, it represents 1 Kg, if we are buying milk, then unit represents 1 liter, on another hand if we talk about buying clothes one unit represents 1 meter.  In this math homework help unit we will learn that if the cost of more than 1 unit ( say n units ) is given and we need to find the cost of 1 unit then what procedure is to be followed.  We will simply divide the total cost by the  number of units i.e. n
It will be more clear with the following examples:
If the cost of 2 kg apples is  250 $, then what is the cost of  a unit Apples?
 Here we are given the cost of  2 kg apples = 250 $
 We observe that the value of n = 2
 So to find the cost of 1 kg apples we will simply divide the total cost of the apples=
   = 250 $ / 2
Or = 125 $
 The same rule works for  larger numbers. Let us try another example: (for more details refer this)
If 15 kg of sugar cost 300 $, find the cost of  a unit of sugar?
 Here we observe that cost of 15 kg sugar is given as = 300 $
 So we have n = 15, thus in order to find the cost of 1 kg ( unit )  of sugar, we need to divide the total cost of the  sugar by 15
 So  unit cost of sugar = 300 / 15
= 20 $ Ans.

In upcoming posts we will discuss about Multiplication facts/tables and Multiplication facts and tables. Visit our website for information on 12th Biology Maharashtra board syllabus